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The P^(H)of an aqueous solution of NH_4 CN( K_a of HCN is 9.2 xx 10^(-10)& K_b of NH_4 OHis 1.8 xx 10^(-5)) |
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Answer» Solution :` pH =7+ ( (PKA- pKb)/(2) )` ` =7+[( (10 -LOG 9.2)- (5 - log 1.8))/(2) ]` |
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