1.

The P^(H) of pure water at 25^(0)C and 35^(0)C are 7 and 6 respectively. The heat of formation of water from H^(+) and OH^(-) will be.

Answer»

`+84.551 KCAL "MOLE"^(-1)`
`-84.551 KCal "Mole"^(-1)`
`+8.4551 KCal "Mole"^(-1)`
`-8.455 KCal "Mole"^(-1)`

Solution :At, `25^(0)C, [H^(+)] = 10^(-7)`
At, `35^(0)C, [H^(+)] = 10^(-6)`
`"log"(K_(omega_(2)))/(K_(omega_(1))) = (DeltaH)/(R)[(T_(2) - T_(1))/(T_(1) xx T_(2))]`


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