InterviewSolution
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InterviewSolution
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The pair in which both species have same magnetic moment (spin only value) is .A. a.`I[Cr(H_(2)O)_(6)]^(2+),[CoCI_(4)]^(2-)`B. b.`[Cr(H_(2)O)]^(2+),[Fe(H_(2)O)_(6)]^(2+)`C. c.`[Mn(H_(2)O)]^(2+),[Cr(H_(2)O)_(6)]^(2+)`D. d.`[CoCI_(4)]^(2-),[Fe(H_(2)O)_(6)]^(2+)` |
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Answer» Correct Answer - B Same magnetic moment =Same number of unpaired electrons `mu=sqrt(n(n+2))` where `n=` number of unpaired electrons `Co^(2+) = 3d^(7), 3` unpaired electrons `Cr^(2+) = 3d^(4), 4` unpaired electrons, `Mn^(2+) = 3d^(5),5` unpaired electrons `Fe^(2+) =3d^(6),4` unpaired electrons. |
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