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The pair of compounds which cannot exist in solution is:A. `Na_(2)CO_(3) and NaHCO_(3)`B. `NaHCO_(3) and NaOH`C. `Na_(2)CO_(3) and NaOH`D. `NaOH and NaCl` |
Answer» Correct Answer - B `NaHCO_(3) ` and NaOH both reacts to form `Na_(2)CO_(3)` `NaHCO_(3) + NaOH to Na_(2)CO_(3) * H_(2)O` |
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