1.

The pair(s) of reagents that yield paramagnetic species is/are

Answer»

Na and excess of `NH_(3)`
K and excess of `O_(2)`
Cu and DILUTE `HNO_(3)`
`O_(2) and 2 - ethylanthraquinol

Solution :If ammonia considered as a liquid then reaction will be
A `M+(x+y)NH_(3)rarr[M(NH)_(3)_(x)]^(+)+[e(NH)_(3)_(y)]^(-)`
B `K+O_(2)rarrKO_(2)[k^(+),O_(2)^(-)`PARAMAGNETIC
C `3Cu+8HNO_(3) rarr3 Cu(NO_(3))+_(2)+2NO+4H_(2)O`


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