The parallax of a heavenly body measured from two points diametrically opposite on equator of Earth is 2^(1). Calculate the distance of the heavenly body. [Given radius of the Earth = 6400 km][1" = 4.85 xx 10^(-6) rad]

The parallax of a heavenly body measured from two points diametrically

1.	The parallax of a heavenly body measured from two points diametrically opposite on equator of Earth is 2^(1). Calculate the distance of the heavenly body. [Given radius of the Earth = 6400 km][1" = 4.85 xx 10^(-6) rad]
Answer» `8.8xx10^(10) m` `4.4 xx 10^(10) m` `0.29xx10^(-10)`m `8.6xx10^(-10)m` SOLUTION :`theta =1 min =(1)/(60)xx (PI)/( 1800) rad` diameterof earth, ` d=a xx R_(e)= 2xx 6400 xx 10^(3) m` DISTANCEOF theheavenlybodyfrom thecentreof the earth,` r= (d) /( theta) =( 2xx 6400 xx 10^(3))/( ((pi)/( 60xx80)))` ` r= 4.4 xx 10^(10) m`