1.

The paramagnetic behaviour of B_(2) is due to the presence of

Answer»

2 unpaired electrons in `pi_(b)MO`
2 unpaired electrons in `pi^(***)MO`
2 unpaired electrons is `sigma^(***)MO`
2 unpaired electron in `sigma_(b)MO`

SOLUTION :`B_(2)` (electrons=10)
`sigma(1s)^(2),sigma*(1s)^(2),sigma(2s)^(2),sigma*(2s)^(2),pi(2p_(X))^(1),pi(2p_(y))^(1)`
THUS, paramagnetic behaviour of `B_(2)` is due to the presence of two unpaired electrons in `pi`- BONDING molecular orbital.


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