Saved Bookmarks
| 1. |
The part of work done by A in 1 day is 1/5th of the part of work done by B in 1 day. A? s 1 day?s work is 3/4th of C?s 1 day?s work. C alone can complete the work in 24 days. In how many days will B alone do the same work ?1). $$8\frac{2}{5}days$$2). $$6\frac{2}{5}days$$3). $$4\frac{2}{5}days$$4). $$3\frac{2}{5}days$$ |
|
Answer» Solution C's 1 day's WORK = $\frac{1}{24}$ => A's 1 day's work = $\frac{3}{4}$ * $\frac{1}{24}$ = $\frac{1}{32}$ => B's 1 day's work = 5 * $\frac{1}{32}$ = $\frac{5}{32}$ $\therefore$ B alone will finish the work in = $\frac{32}{5}$ days = 6$\frac{2}{5}$ days |
|