1.

The partial pressure of carbon dioxide in the reaction CaCO_3(s) hArr CaO(s)+ CO_2(g) is 1.017 xx 10^(-3) atm at 500^@C. Calculate K_P" at " 600^@C for the reaction. DeltaH for the reaction is 181 kJ mol^(-1) and does not change in the given range of temperature.

Answer»

Solution :`P_(CO_2) = 1.017 XX 10^(-3)a t m, T = 500^@C`
`K_P = P_(CO_2)`
`:. K_(P_1) = 1.017 xx 10^(-3), T= 500 + 273 = 773 K`
`K_(P_2) = ?, T = 600+ 273 = 873 K`
`DeltaH^@ = 181 kJ mol^(-1)`
`log""((K_(P_2))/K_(P_1)) = (DeltaH^@)/(2.303 R) ((T_2-T_1)/(T_1T_2))`
`log""(K_(P_2)/(1.017 xx 10^(-3)))=(181xx 10^3)/(2.303 xx 8.314) ((873 - 773)/(873 xx 773))`
`log""(K_(P_2)/(1.017 xx 10^(-3))) = (181xx 10^3xx 100)/(2.303 xx 8.314 xx 873 xx 773)`
`K_(P_2)/(1.017xx 10^(-3))`= ANTILOG of (1.40)
`K_(P_2)/(1.017xx 10^(-3)) = 25.12`
`rArr K_(P_2) = 25.12 xx 1.017 xx 10^(-3)`
`K_(P_2) = 25.54 xx 10^(-3)`


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