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The partial pressure of carbon dioxide in the reaction CaCO_3(s) hArr CaO(s)+ CO_2(g) is 1.017 xx 10^(-3) atm at 500^@C. Calculate K_P" at " 600^@C for the reaction. DeltaH for the reaction is 181 kJ mol^(-1) and does not change in the given range of temperature. |
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Answer» Solution :`P_(CO_2) = 1.017 XX 10^(-3)a t m, T = 500^@C` `K_P = P_(CO_2)` `:. K_(P_1) = 1.017 xx 10^(-3), T= 500 + 273 = 773 K` `K_(P_2) = ?, T = 600+ 273 = 873 K` `DeltaH^@ = 181 kJ mol^(-1)` `log""((K_(P_2))/K_(P_1)) = (DeltaH^@)/(2.303 R) ((T_2-T_1)/(T_1T_2))` `log""(K_(P_2)/(1.017 xx 10^(-3)))=(181xx 10^3)/(2.303 xx 8.314) ((873 - 773)/(873 xx 773))` `log""(K_(P_2)/(1.017 xx 10^(-3))) = (181xx 10^3xx 100)/(2.303 xx 8.314 xx 873 xx 773)` `K_(P_2)/(1.017xx 10^(-3))`= ANTILOG of (1.40) `K_(P_2)/(1.017xx 10^(-3)) = 25.12` `rArr K_(P_2) = 25.12 xx 1.017 xx 10^(-3)` `K_(P_2) = 25.54 xx 10^(-3)` |
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