1.

The partial pressure of carbon dioxide in the reaction CaCO_(3)(s)hArrCaO(s)+CO_(2)(g) is 1.017xx10^(-3) atm at 500^(@)C. Calculate K_(P) at 600^(@)c C for the reaction. DeltaH for the reaction is 181 kJ mol^(-1) and does not change in the given range pf temperature.

Answer»

SOLUTION :`P_(CO_(2))=1.017xx10^(-3)" atm "T=500^(@)C`
`K_(P)=P_(CO_(2))`
`:.L_(P_(1))=1.017xx10^(-3),T=500+273=773K`
`K_(P_(1))=?""T=600+273=873K`
`DeltaH^(@)=181" kJ mol"^(-1)`
`"LOG"((K_(P_(2)))/(K_(P_(1))))=(DeltaH^(@))/(2.303R)((T_(2)-T_(1))/(T_(1)T_(2)))`
`"log"((K_(P_(2)))/(1.017xx10^(-3)))=(181xx10^(3))/(2.303xx8.314)((873-773)/(873xx773))`
`"log"((K_(P_(2)))/(1.017xx10^(-3)))=(181xx10^(3)xx100)/(2.303xx8.314xx873xx773)`
`(K_(P_(2)))/(1.017xx10^(-3))="anti log of "(1.40)`
`(K_(P_(2)))/(1.017xx10^(-3))=25.12`
`rArr" "K_(P_(2))=25.12xx1.017xx10^(-3)`
`K_(P_(2))=25.54xx10^(-3)`


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