Saved Bookmarks
| 1. |
The partial pressure of carbon dioxide in the reaction CaCO_(3)(s)hArrCaO(s)+CO_(2)(g) is 1.017xx10^(-3) atm at 500^(@)C. Calculate K_(P) at 600^(@)c C for the reaction. DeltaH for the reaction is 181 kJ mol^(-1) and does not change in the given range pf temperature. |
|
Answer» SOLUTION :`P_(CO_(2))=1.017xx10^(-3)" atm "T=500^(@)C` `K_(P)=P_(CO_(2))` `:.L_(P_(1))=1.017xx10^(-3),T=500+273=773K` `K_(P_(1))=?""T=600+273=873K` `DeltaH^(@)=181" kJ mol"^(-1)` `"LOG"((K_(P_(2)))/(K_(P_(1))))=(DeltaH^(@))/(2.303R)((T_(2)-T_(1))/(T_(1)T_(2)))` `"log"((K_(P_(2)))/(1.017xx10^(-3)))=(181xx10^(3))/(2.303xx8.314)((873-773)/(873xx773))` `"log"((K_(P_(2)))/(1.017xx10^(-3)))=(181xx10^(3)xx100)/(2.303xx8.314xx873xx773)` `(K_(P_(2)))/(1.017xx10^(-3))="anti log of "(1.40)` `(K_(P_(2)))/(1.017xx10^(-3))=25.12` `rArr" "K_(P_(2))=25.12xx1.017xx10^(-3)` `K_(P_(2))=25.54xx10^(-3)` |
|