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The particle executing simple harmonic motion has a kinetic energy K0 cos^2 ωt. The maximum values of the potential energy and the total energy are respectively ___________(a) Kc/2 and K0(b) K0 and K0(c) K0 and 2K0(d) 0 and 2K0 |
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Answer» The correct option is (b) K0 and K0 For explanation: When kinetic energy is maximum, potential energy is zero and vice-versa. But Kinetic energy+ Potential energy = Total energy Maximum potential energy = Maximum kinetic energy = Total energy = K0. |
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