Saved Bookmarks
| 1. |
The particle P shown in the figure has a mass of 10 mg and a charge of `-0.01 muC`. Each plate has a surface area `10^(-2) m^2` on one side. What potential difference V should be applied to the combination to hold the particle P in equilibrium? A. `43 mV`B. `35 mV`C. ` 50 mV`D. `55 mV` |
|
Answer» Correct Answer - A `mg=qE,` where `E=` electric field or `mg=q(V)/(d)` (where `d=` separation at the plates) `=q(V)/(2) (therefore (epsilon_(0)A)/(d)=C(1)/(d)=(C)/(epsilon_(0)A))` or `V=(2"mg"epsilon)A)/(qC)` `=(10^(-4)xx10xx2.2xx10^(-12)xx10^(-2))/(10^(-8)xx0.04xx10^(-6))` `=(10^(-4)xx9.8xx8.88xx10^(-12))/(10^(-4)xx0.04xx10^(-6))` `=43mV` |
|