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The particular solution of the differential equation `log ((dy)/(dx)) = x`, when x = 0 , y = 1 is …..A. `y = e^(x) + 2`B. `y = - e^(x)`C. `y = - e^(x) + 2`D. `y = e^(x)` |
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Answer» Correct Answer - D We have, differential equations. `log ((dy)/(dx)) = x implies (dy)/(dx) = e^(x)` `implies dy = e^(x) dx` Integrating on both sides, we get `int dy = int e^(x) dx` `implies y = e^(x) + C` On putting x = 1, is Eq. (i) we get `1 = e^(0) + C implies C = 0` Now, particular solution of the given differential is `y = e^(x)` |
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