The passage of current liberates `H_2` at cathode and `Cl_2` at anode. The solution isA. copper chloride in waterB. NaCl in waterC. `H_2SO_4`D. Water

The passage of current liberates `H_2` at cathode and `Cl_2` at anode.

1.	The passage of current liberates `H_2` at cathode and `Cl_2` at anode. The solution isA. copper chloride in waterB. NaCl in waterC. `H_2SO_4`D. Water
Answer» Correct Answer - B Since discharge potential of watier is greater than that of sodium so water is reduced at cathode instead of `Na^(+)`. Cathode: `H_(2)O+e^(-)to(1)/(2)H_(2)+OH^(-)` Anode: `Cl^(-)to(1)/(2)Cl_(2)+e^(-)`.

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The passage of current liberates `H_2` at cathode and `Cl_2` at anode. The solution isA. copper chloride in waterB. NaCl in waterC. `H_2SO_4`D. Water

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