The path difference between the two waves y_(1) = a_(1) sin (omega t - (2pi x)/(lambda)) and y_(2) = a_(2) cos (omega t - (2pi x)/(lambda) + phi) is ……….

The path difference between the two waves y_(1) = a_(1) sin (omega t -

1.	The path difference between the two waves y_(1) = a_(1) sin (omega t - (2pi x)/(lambda)) and y_(2) = a_(2) cos (omega t - (2pi x)/(lambda) + phi) is ……….
Answer» `(lambda)/(2pi)"" PHI` `(lambda)/(2pi) ( phi + (PI)/(2))` `(2pi)/(lambda) (phi + (pi)/(2))` `(2pi)/(lambda) "" phi` Solution :PHASE difference = `phi + (pi)/(2)` , PATH difference = `(lambda)/(2) (phi + (pi)/(2))`