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The pendulum of certain clock has time period 2.04 s. How fast or slow does the clock run during 24 hours? |
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Answer» Now no of OSCILLATION in 1 day `=(24xx3600)/2` =43200 But in each oscillation it is slower by `(2.04-2.00)=00.04sec` So in ONE day it is slower by `=43200xx(0.04)` `=28.8min` so, the clock runs 28.8 minutes slowere in one day. |
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