The percentage by volume of C_(3)H_(8) in a gaseous mixture of C_(3)H_(8),CH_(4)andCO is 20. When 10 ml of the mixture is burnt in excess of O_(2), the volume of CO_(2) produced is 2xml. Find the value of .x..

The percentage by volume of C_(3)H_(8) in a gaseous mixture of C_(3)H_

1.	The percentage by volume of C_(3)H_(8) in a gaseous mixture of C_(3)H_(8),CH_(4)andCO is 20. When 10 ml of the mixture is burnt in excess of O_(2), the volume of CO_(2) produced is 2xml. Find the value of .x..
Answer» SOLUTION :20% of 10 ml =2 ml Let VOLUME of `CH_(4)=x` `implies CO=(8-x)ml` `{:(C_(3)H_(8)+5O_(2),rarr,3CO_(2)+4H_(2)O),("2 ml",rarr,"6 ml"),(CH_(4)+2O_(2),rarr,CO_(2)+2H_(2)O),("x ml",rarr,"x ml"),(CO+(1)/(2)O_(2),rarr,CO_(2)),((8-x)ml,rarr,(8-x)ml):}` `V_(CO_(2))=6+x+(8-x)=14ml`