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The percentage composition by mass of an aqueous solution of a solute (molecular mass 150 which boils at 373.26 is (K_(b) = 0.52) |
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Answer» 5 `m = (W_(2) xx 1000)/(M_(2) xx W_(1)(g)) :. 0.5 = (W_(2) xx 100)/(150 xx 1000)` `W_(2) = 150 xx 0.5 = 75 g ` %age by mass `=75/1075 xx 100 = 7% "APPROX".` |
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