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The percentage composition of a compound `C=90%` and `H=10%`. A possible formula of the compounds isA. `C_(8)H_(10)`B. `C_(15)H_(30)`C. `C_(15)H_(20)`D. `C_(15)H_(15)` |
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Answer» Correct Answer - C `C:H=90/12:10/1=3:4` Therefore empirical formula `=C_(3)H_(4)`. Since M.F. in `n` times E.F., therefore the M.F. of the hydrocarbon `=C_(15)H_(20)` |
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