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The percentage error in the mass and speed are 2% and 3% respectively. What is the maximum error in kinetic energy calculated using these quantities ? |
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Answer» (∆M/M) x 100 = 2%; (∆V/V) × 100 = 3%; Kinetic energy = (1/2) mV2 (∆K/K) x 100 = (∆M/M) × 100 + (2∆V/V) × 100 = 2 + 2(3) = 2 + 6 = 8% |
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