1.

The percentage error in the measurement of the radius of a sphere is 1.5%. What would be the percentage error in the volume of the sphere ?

Answer» Let the radius of the sphere=`r pm Deltar `
Then according to the question , `(Deltar)/rxx100`=1.5%
or`(Deltar)/r`=0.015
Volume of the sphere is `V=4/3pir^3`
As per the rule for combination of errors for exponents `(DeltaV)/V=3(Deltar)/r`
=3 x 0.015
`(DeltaV)/V`=0.045
Percentage error =`(DeltaV)/Vxx100=0.045xx100=4.5%`


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