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The percentage error in the measurement of the radius of a sphere is 1.5%. What would be the percentage error in the volume of the sphere ? |
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Answer» Let the radius of the sphere=`r pm Deltar ` Then according to the question , `(Deltar)/rxx100`=1.5% or`(Deltar)/r`=0.015 Volume of the sphere is `V=4/3pir^3` As per the rule for combination of errors for exponents `(DeltaV)/V=3(Deltar)/r` =3 x 0.015 `(DeltaV)/V`=0.045 Percentage error =`(DeltaV)/Vxx100=0.045xx100=4.5%` |
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