The percentage loss in mass after heating a pure sample of potassium chlorate (Molecular mass = 122.5 g/mole) will be:

The percentage loss in mass after heating a pure sample of potassium c

1.	The percentage loss in mass after heating a pure sample of potassium chlorate (Molecular mass = 122.5 g/mole) will be:
Answer» tion:2KClO 3 →2KCl+3O 2 molar MASS of KClO 3 = 122.5 gmass of KCl = 74.5 gso, PERCENTAGE LOSS = 122.5122.5−74.5 ∗100=39.18%