1.

The percentage of an element M is 53 in its oxide of molecular formula M_(2)O_(3). Its atomic mass is about:

Answer»

45
9
18
27

Solution :Equivalent MASS of element `=("Mass of element")/("Mass of oxygen")XX8`
`=(53)/(47)xx8=9`
ATOMIC mass=Equivalent mass `xx` Valency
`=9xx3=27` AMU.


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