1.

The percentage of C in methanoic anhydride is ........

Answer»

64.86
32.43
3.243
31.43

Solution :Methanoic anhydride is `H-overset(O) overset(||)C-O-overset(O)overset(||)C-H`
It is `H_(2)C_(2)O_(3)` and its molar mass
`= 2(H) +2(C) +3(O)`
`=2(1)+2(12)+3(16)`
`=2+24+48= 74 g mol^(-1)`
1 MOLE `H_(2)C_(2)O_(3)` has 24 g carbon,
`% C = (24xx100)/(74) = 32.432~~32.43%`


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