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The percentage of element M is 53 in its oxide of molecular formula `M_(2)O_(3)`. Its atomic mass is aboutA. `45`B. `9`C. `18`D. `36` |
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Answer» Correct Answer - C If m is the atomic mass of the element M, then 2m + 48g of `M_(2)O_(3)` contain O = 48 g `:.` % of O in `M_(2)O_(3) = (48)/(2m+48)xx100=53` `:. 2m + 48 = (4800)/(53)=90.56` or 2m = 42.56 or m = `21.28 ~~ 22` |
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