1.

The percentage of ionic character of LiH is 76.81% and the bond length is 1.596Å. Wha is the value of dipole moment of LiH molecule? [1D=3.335xx10^(-30)C*m]

Answer»

Solution :If the molecule is 100% ionic, then
`mu_("ionic")=qxxd=1.602xx10^(-19)Cxx1.596xx10^(-10)m`
`=2.557xx10^(-29)C*m`
`%` ionic CHARACTER`=(mu_("observed"))/(mu_("ionic"))XX100`
`thereforemu_("observed")=("% ionic character"xxmu_("ionic"))/(100)`
`=(76.81xx2.557x10^(-29))/(100)=1.96xx10^(-29)C*m`
`=(1.96xx10^(-29))/(3.335xx10^(-30))D=5.07D`


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