1.

The percentage of N_(2) in urea is about

Answer»

85
46
28
18

Solution :Molecular mass of urea `(NH_(2)CONH_(2)) = 60`
Amount of `N_(2)` in ONE mole = 28
`RARR` % of `N_(2)` in urea `= (28)/(60) xx 100 = 46.6%`


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