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The percentage of nitrogen in urea is about:A. 28B. 18C. 85D. 46

Answer» Correct Answer - D
The formula of urea = `NH_(2) CONH_(2)`
Molar mass of urea `=14 + (2 xx 1) + 12 + 16 + 14 + (2 xx 1)`
`=60 "g mol"^(-1)`
Nitrogen = 28 g `"mol"^(-1)`
`therefore %` of N_(2) in urea `= 28/60 xx 10 = 46.6%cong 46%`
Hence, the percentage of `N_(2)` in urea `=46.6%cong 46%`


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