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The percentage of nitrogen in urea is about:A. 28B. 18C. 85D. 46 |
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Answer» Correct Answer - D The formula of urea = `NH_(2) CONH_(2)` Molar mass of urea `=14 + (2 xx 1) + 12 + 16 + 14 + (2 xx 1)` `=60 "g mol"^(-1)` Nitrogen = 28 g `"mol"^(-1)` `therefore %` of N_(2) in urea `= 28/60 xx 10 = 46.6%cong 46%` Hence, the percentage of `N_(2)` in urea `=46.6%cong 46%` |
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