1.

The percentage of p-character of the hybrid orbitals in graphite and diamond are respectively

Answer»

33 and 25
50 and 75
67 and 75
33 and 75

Solution :Hybridisation in graphite = `sp^(2)`
`therefore %` p-character = `(2)/(3) XX100 = 67%`
Hybridisation in diamond = `sp^(3)`
`therefore %` p-character `= (3)/(4)xx100 = 75%` .


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