1.

The percentage of pyridine (C_5H_5N) that forms pyridinium ion (C_5H_5NH) in a 0.10 M aqueous pyridine solution (K_b for C_5H_5N=1.7 times 10^-9) is………..

Answer»

`0.006%`
`0.013%`
`0.77%`
`1.6%`

Solution :`C_5H_5N+H-OH leftrightarrowC_5H_5NH+OH^(-)`
`(a^2C)/(1-a)=K_b`
`a^2C approxK_b`
`a=sqrt((K_b)/C)sqrt((1.7 times 10^-9)/(0.1))=sqrt1.7 times 10^-4`
Percentage of DISSOCIATION
`sqrt1.7 times 10^-4 times 100=1.3 times 10^-2=0.013%`


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