The percentage of pyridine (CsH&N) that formspyridinium ion (CsH,N'H)

1.	The percentage of pyridine (CsH&N) that formspyridinium ion (CsH,N'H) in a 0.10 M aqueouspyridine solution (K, for C,H,N 1.7 x10-9) is
Answer» C5H5N + H2O ----> C5H5N^+ H + OH- We know that, α = √(Kb/M) where α --- degree of dissociation or association Kb --- boiling point elevation constant M --- Molarity α = √(1.7×10^-9)/0.1 = √1.7×10^-8 = 1.3 × 10^-4 Percentage : α % = 1.3 × 10^-4 × 100 = 0.013% ok thanks

The percentage of pyridine (CsH&N) that formspyridinium ion (CsH,N'H) in a 0.10 M aqueouspyridine solution (K, for C,H,N 1.7 x10-9) is

Answer»

C5H5N + H2O ----> C5H5N^+ H + OH-

We know that,

α = √(Kb/M)

where

α --- degree of dissociation or association

Kb --- boiling point elevation constant

M --- Molarity

α = √(1.7×10^-9)/0.1

= √1.7×10^-8

= 1.3 × 10^-4

Percentage :

α % = 1.3 × 10^-4 × 100

= 0.013%

ok thanks