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The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic mass = 78.4). Then minimum molecular mass of peroxidase anhydrous enzyme is _____.(A) 1.568 x 104 (B) 1.568 x 103 (C) 15.68 (D) 3.136 x 104 |
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Answer» Correct option: (A) 1.568 x 104 Since, 0.5 g Se ≡ 100 gm peroxidase anhydrous enzyme ∴ 78.4 g Se = \(\cfrac{100\, \times \, 78.4}{0.5}\) = 1.568 x 104 Minimum molecular mass of peroxidase anhydrous enzyme means molecule atleast contains one selenium atom. |
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