1.

The percentage of sulphur in an organic compound whose 0.32g produces 0.233g of BaSO_(4) [At. Wt. Ba=137, S=32] is

Answer»

`1.0`
`10.0`
`23.5`
`32.1`

SOLUTION :% of S`=(32)/(233)TIMES(0.33)/(0.32)times100=10%`


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