1.

The percentageof p-character in SF_(6) are

Answer»

`120^(@), 20%`
`90^(@), 33%`
`109^(@), 25%`
` 90^(@), 25%`

Solution :`SF_(6)` involves `sp^(3) d^(2)` hybridization . The shape is
octahedral with each bond angle = `90^(@)`.
% of d-character
`=("2(no. of d-ORBITALS)")/("6(total no.of hybrid orbitals ")XX100 = 33%`.


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