The perimeters of two similar triangles are 25 cm and 15 cm respective

1.	The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of first triangle is 9 cm, what is the corresponding side of the other triangle?
Answer» Assume ABC and PQR to be 2 triangle. We, have ΔABC ~ΔPQR Perimeter of ΔABC = 25 cm Perimeter of ΔPQR = 15 cm AB = 9 cm PQ = ? Since, ΔABC ~ΔPQR Then, ratio of perimeter of triangles = ratio of corresponding sides So \(\frac{25}{15}\) = \(\frac{AB}{PQ}\), (Corresponding parts of similar triangle area proportion) Or \(\frac{25}{15}\) = \(\frac{9}{PQ}\) Or PQ = 135/25 Or PQ = 5.4 cm

The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of first triangle is 9 cm, what is the corresponding side of the other triangle?

Answer»

Assume ABC and PQR to be 2 triangle.

We, have

ΔABC ~ΔPQR

Perimeter of ΔABC = 25 cm

Perimeter of ΔPQR = 15 cm

AB = 9 cm

PQ = ?

Since, ΔABC ~ΔPQR

Then, ratio of perimeter of triangles = ratio of corresponding sides

So \(\frac{25}{15}\) = \(\frac{AB}{PQ}\), (Corresponding parts of similar triangle area proportion)

Or \(\frac{25}{15}\) = \(\frac{9}{PQ}\)

Or PQ = 135/25

Or PQ = 5.4 cm