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The perio of oscillation of a magnet in vibration magnetometer is 2 sec. The period of oscillation of a magnet whosr magnetic moment is four times that of the first magnet isA. 8sB. 4sC. 1sD. 0.5 s |
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Answer» Correct Answer - C The tme period `T=2pi sqrt(I//MB_(H))` Thus `(T_(2))/(T_(1)) = sqrt((M_(1))/(M_(2)))=sqrt((1)/(4)) =(1)/(2)` `or T_(2) = 2 xx I//2` = 1 sec the answer is (3) 1 sec |
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