1.

The perio of oscillation of a magnet in vibration magnetometer is 2 sec. The period of oscillation of a magnet whosr magnetic moment is four times that of the first magnet isA. 8sB. 4sC. 1sD. 0.5 s

Answer» Correct Answer - C
The tme period
`T=2pi sqrt(I//MB_(H))`
Thus `(T_(2))/(T_(1)) = sqrt((M_(1))/(M_(2)))=sqrt((1)/(4)) =(1)/(2)`
`or T_(2) = 2 xx I//2`
= 1 sec the answer is (3) 1 sec


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