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The period of 0scillation of a simple pendulum is recorded as 2.63s, 2.56s,2.42s ,2.71s and 2.80s respectively. The average absolute error is .............. |
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Answer» SOLUTION :Mean ABSOLUTE ERROR = `(sum|Detla T_i|)/(n)` ` Delta T_m = (0.01+ 0.06 + 0.20 + 0.90 + 0.18 )/(5)` `Delta T_m = (0.54)/(5) = 0.108 s= 0.11 s ` (Rounded of to 2ND DECIMAL place ) |
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