1.

The period of 0scillation of a simple pendulum is recorded as 2.63s, 2.56s,2.42s ,2.71s and 2.80s respectively. The average absolute error is ..............

Answer»

SOLUTION :Mean ABSOLUTE ERROR = `(sum|Detla T_i|)/(n)`
` Delta T_m = (0.01+ 0.06 + 0.20 + 0.90 + 0.18 )/(5)`
`Delta T_m = (0.54)/(5) = 0.108 s= 0.11 s ` (Rounded of to 2ND DECIMAL place )


Discussion

No Comment Found