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The period of a particle in SHM is `8s`. At `t=0` it is at the mean position. The ratio of the distances travled by it in the first and the second second isA. `(1)/(2)`B. `(1)/(sqrt(2))`C. `sqrt(2)`D. `sqrt(2)+1` |
Answer» Correct Answer - D `y_(1) =Asin ((2pi)/(T)xxt_(1)), y_(2) = A sin ((2pi)/(T)xx(t_(1)+t_(2)))` Distance travelled in second, `y_(2)^(1) = y_(2) - y_(1)` |
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