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The period of a simple harmonic oscillator is 2 s. If it crosses mean position at an instant. The time after which its displacement from the mean position will be half of the amplitude is.A. `(1//8)s`B. `(1//6)s`C. `(1//4)s`D. `(1//2)s` |
Answer» Correct Answer - B `x=Asinomegat` `(1)/(2)A=Asinomegat` `omegat=sin^(-1)((1)/(2))=(pi)/(6)` `(2pi)/(T)t=(pi)/(6)` `t=(T)/(12)=(2)/(12)=(1)/(6)s` |
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