The period of a simple pendulum on the surface of the earth is 2s. Find its period on the surface of this moon, if the acceleration due to gravity on the moon is one-sixth that on the earth ?

The period of a simple pendulum on the surface of the earth is 2s. Fin

1.	The period of a simple pendulum on the surface of the earth is 2s. Find its period on the surface of this moon, if the acceleration due to gravity on the moon is one-sixth that on the earth ?
Answer» Solution :`T_1 = 2S , T_2 `(moon) `=2PI sqrt(l//g_2) ,T_2 =T_1sqrt(g(g//6))=2 xxsqrt6 = 4.89 ` SECOND .