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The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.A. 0.1 sB. 0.11 sC. 1.0 sD. 0.01 s |
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Answer» Correct Answer - 2 `"Average value"=(2.63+2.56+2.42+2.71+2.80)/(5)` `=2.62 sec.` `"Now " |/_T_(1)|=2.63-2.62=0.01` `|/_T_(2)|=2.62-2.56=0.06` `|/_T_(3)|=2.62-2.42=0.20` `|/_T_(4)|=2.71-2.62=0.09` `|/_T_(5)|=2.80-2.62=0.18` Mean absolute error `/_T=(|/_T_(1)|+|/_T_(2)|+|/_T_(3)|+|/_T_(4)|+|/_T_(5)|)/(5)` `/_T=(0.54)/(5)=0.108=0.11sec.` |
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