1.

The period of oscillation of a simple pendulum in the experiment is recorded as `2.63s, 2.56s, 2.42s, 2.71s` and `2.80s` respectively. The average absolute error isA. 0.1sB. 0.11sC. 0.01sD. 1.0s

Answer» Mean value `veca=(2.63+2.56+2.42+2.71+.2.80)/(5)`
`vec=2.624`
absolute error in various readings are
`Deltaa_(1)=2.624-2.63=-.006`
`Deltaa_(2)=2.624-2.56=0.64`
`Deltaa_(3)=2.624-2.42=-204`
`Deltaa_(42.624-2.71=-.086`
`Deltaa_(5)=2.624-2.80=-.176`
`overlineDeltaa=(|Deltaa_(1)|+|Deltaa_(2)|+|Deltaa_(3)|+|Deltaa_(4)|+|Deltaa_(5)|)/(5)`
`=0.11` sec


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