1.

The period of oscillation of a simple pendulum is given by T=2pi sqrt((l)/(g)). In finding the value of g, which quantity should be measured most accurately and why?

Answer»

Solution :`T=2pi sqrt((L)/(g)) rArr T^(2)=(4pi^(2)l)/(g)`
`or g=4pi^(2)(l)/(T^(2))`
`therefore"Fractional ERROR in g"=(DELTAG)/(g)=(Deltal)/(l)+(2DeltaT)/(T)`
Note that any error in T is doubled up. Therefore, time should be measured most accurately.


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