The period of revolution of planet A around the Sun is 8 times that of B. The distance of A from the Sun is how many times greater than that of B from the Sun.

The period of revolution of planet A around the Sun is 8 times that of

1.	The period of revolution of planet A around the Sun is 8 times that of B. The distance of A from the Sun is how many times greater than that of B from the Sun.
Answer» 2 3 4 5 Solution :`((T_(A))/(T_(B)))^(2)=((a_(A))/a_(B))^(2)RARR((8T_(B))/(T_(B)))^(2/3) =(a_(A))/(a_(B))` `T_(A) =8T_(B) rArr(8)^(2/3) a_(B) = a_(A) rArr a_(A) = 4a_(B)`