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The periodic time of simple pendulum is T = 2π√(ℓ/g) relative error in the measurement of T and ℓ are ±a and ±b respectively find relative error in the measurement of g(a) a + b (b) 2b + a (c) 2a + b (d) a – b |
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Answer» (c) 2a + b Explanation: T = 2π √(ℓ/g) ∴ T2 = (2π)2(ℓ/g) ∴ g = [(4π2ℓ) / (T2)] (Δg / g) = (Δℓ / ℓ) + 2 (ΔT / T) = b + 2a |
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