1.

The periodic time (T) of a simple pendulum of length (L) is given by `T=2pisqrt((L)/(g))`. What is the dimensional formula of `Tsqrt((g)/(L))`?A. `[M^(0)L^(1)T^(0)]`B. `[M^(0)L^(0)T^(0)]`C. `[M^(1)L^(1)T^(-1)]`D. `[M^(0)L^(-1)T^(1)]`

Answer» Correct Answer - b
`because T=2pisqrt((L)/(g)) therefore (T)/(sqrt((L)/(g)))=Tsqrt((g)/(L))=2pi`
But `2pi` is a constant and it has the dimensions of `M^(0)L^(0)T^(0)`
`therefore` The dimensional formula for `Tsqrt((g)/(L))` is `[M^(0)L^(0)T^(0)]`


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