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The perpendicular from the origin to a line meets it at the point (-2, 9), find the equation of the line. |
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Answer» Slope of the line through the origin and (-2, 9) = \(\frac{y_2 - y_1}{x_2 - x_1} = \frac{9-0}{-2-0} = -\frac{9}{2}\) Then the slope of the required line is \(\frac{2}{9}\). Hence the equation is y – y1 = m(x – x1) ⇒ y – 9 = \(\frac{2}{9}(x - (-2))\) ⇒ 9y – 81 = 2x + 4 ⇒ 2x – 9x + 85 = 0. |
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