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The pH of 0.005 M codeine (C_(18)H_(21)NO_(3)) solution is 9.95. Calculate its ionization constant and pK_(b). |
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Answer» Form GIVEN pH, `[H^(+)] = 1.12xx10^(-10) M` `:. [OH^(-)] = (K_(w))/([H^(+)]) = (10^(-14))/(1.12xx10^(-10))=8.93xx 10^(-5)M` `K_(B) = ([B^(+)] [OH^(-)])/([BOH]) = ((8.93xx10^(-5))^(2))/(0.005)=1.6xx10^(-6)`. |
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