1.

The pH of 0.005 M codeine (C_(18)H_(21)NO_(3)) solution is 9.95. Calculate its ionization constant and pK_(b).

Answer»


Solution :CODEINE + water `hArr` codeniumion + `OH^(-)`
Form GIVEN pH, `[H^(+)] = 1.12xx10^(-10) M`
`:. [OH^(-)] = (K_(w))/([H^(+)]) = (10^(-14))/(1.12xx10^(-10))=8.93xx 10^(-5)M`
`K_(B) = ([B^(+)] [OH^(-)])/([BOH]) = ((8.93xx10^(-5))^(2))/(0.005)=1.6xx10^(-6)`.


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