Saved Bookmarks
| 1. |
The pH of 0.05 M aqueous solution of diethyl amine is 12.0. The K_(b) = x xx 10^(-3) then what is x value? |
|
Answer» ` pOH= (1)/(2) (pK_b -log C) ` ` 2= (1)/(2) (pK_b-log ( 5 xx10 ^(_2))) ` `pK_b -log 5 +2=4 rArr pK_b =2+ 0.7=2.7` ` -log K_b =2.7 rArr K_b = 10 ^(-2.7)=10 ^(-3+0.3) ` Anti log ` (0.3 ) xx 10 ^(-3)= 2XX 10 ^(-3) ` |
|