1.

The pH of 0.1 M acetic acid is 3, the dissociation constant of acid will be

Answer»

`1.0 xx 10^(-4)`
`1.0 xx 10^(-5)`
`1.0 xx 10^(-3)`
`1.0 xx 10^(-8)`

Solution :`pH = 3, [H^(+)] = 10^(-3)M`
`because [H^(+)] = sqrt(K xx C)`
`[10^(-3)]^(2) = K xx c, ([10^(-6)])/(0.1) = K = 10^(-5)`.


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